##EOF## in 7.409 - Resolved

[MacschedStudent]

Hey Guys I have never used the logic in this way before - I'm trying to count the lines in a simple text file so to simplify the test I created a text file with only one line. I double-checked to make sure there was no blank space after the line then I ran the standard RLN code to count the lines

Code: Select all

Let>x=1
Label>cstart
ReadLn>Cntr.log,x,linex
MessageModal>linex
If>linex=##EOF##,cfinish
MessageModal>x
Let>x=x+1
Goto>cstart
Label>cfinish

MessageModal>x

to my surprise the result returned was 2 - how can this be ? Is the logic in 7.409 counting the ##EOF## as an additional line. I then added:

x=x-1 at the end of the code and got the correct line count...any ideas..??

[Marcus Tettmar]

It's not Macro Scheduler counting the EOF, it's your script. Look carefully at your script. YOU are counting the EOF. Hint: You're initialising x to 1 and incrementing it after each line has been read. So after the first line has been read x is now 2. You then go back up to the top of the loop and get EOF and then jump out. x is now 2.

[MacschedStudent]

Marcus :

It took me a minute but your right:

when line 1 is read its not at the end: it still has to loop back to cstart to find the ##EOF## line and because it passes through the increment x logic when it gets to the top again the count will always be 2
DuuuuuuuuuuuuHHH!!

I guess I will keep the x-1 statement. Because if I attempt to start with x=0 it wont work because there is no line 0. - Thanks Marcus

[Marcus Tettmar]

Either:

1) Keep x-1 at the end

Or

2) Initialise to zero but read line x+1 each time

Or

3) If you just want to know how many lines are in a text file, just do this:

ReadFile>filename,filedata
Separate>filedata,CRLF,lines
MessageModal>lines_count